Author Topic: Divided By 12 Technique  (Read 13372 times)

Code Blue

  • Newbie
  • *
  • Posts: 24
Divided By 12 Technique
« on: November 23, 2010, 02:25:03 AM »
   

 
"En Prison"

1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 2nd Dozen, 2nd Column Of 12, And Numbers 7,10,27,30
27 Chips On 0, And 00
77 Total
2,700 Buy-In
2nd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,10,27,30
3 Chips On 2nd Dozen, And 2nd Column Of 12
32.5 Chips On 0, And 00
92 Chips Total
3,300 Buy-In
3rd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,17,20,25,27,28,30
4 Chips On 2nd Dozen, And 2nd Column Of 12
41 Chips On 0, And 00
116 Total
4,200 Buy-In
4th
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 17,20,2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,25,27,28,30
6 Chips On 2nd Dozen, And 2nd Column Of 12
43 Chips On 0, And 00
122 Total
4,800 Buy-In

Roulette Xtreme "Don't Apply Any Rules"

1st
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 2nd Dozen, 2nd Column Of 12, And Numbers 7,10,27,30
11 Chips On 0, And 00
45 Total
2,700 Buy-In
2nd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,10,27,30
3 Chips On 2nd Dozen, And 2nd Column Of 12
17 Chips On 0, And 00
61 Chips Total
3,300 Buy-In
3rd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,17,20,25,27,28,30
4 Chips On 2nd Dozen, And 2nd Column Of 12
26 Chips On 0, And 00
86 Chips Total
4,200 Buy-In
4th
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 17,20,2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,25,27,28,30
6 Chips On 2nd Dozen, And 2nd Column Of 12
32 Chips On 0, And 00
100 Total
4,800 Buy-In

See If You Can Get Through All Four Levels Doubling Up As You Go Until You Reach The Top At 9,600 chips. If You Get On a Winning Streak, Just Let It Go Until You Win As Many Chips As You Want, Or You Reach The 9,600 Chip Mark That We're Looking For. If You Don't Reach Your Goal, Start Over From The Beginning. OK? Good Luck!!!

The Way The Inside Bets Work In These Examples Is By Using The Same Number Of Chips On Each Column, Or Dozen. In The First Betting Example Listed Above Under, "En Prison" That Number Is 9 Chips. Let's Take The 1st Dozen For Example: First We Need To Add Up All The Inside Bets That Are In Conjunction With This Dozen. Those Bets Are The 1 Chip Bets On 9,12,2/5. Plus, The 2 Chips Bet On 7, And 10. Then, We Need To Factor In The 2 Chips Bet On The Outside Of The Layout That Are In Relation To This Dozen. That Bet Is The 2 Chips On The 2nd Column Of 12. Which Brings Our The Total Chip Count For This Dozen To 9 Chips.

Now Let's Look At The Column Bets. Using The 2nd Column For Example: There Are 5 Inside Bets In Relation To This Column. They're The Chips Bet On 17,20,2/5,17/20,32/35. Then, I Included The 2 Outside Bets Which Are The 2 Chips Bet On The 2nd Dozen, And 2nd Column Of 12. That Gives Us Our 9 Chip Total For This Column. The Same Thing Will Happen With All Of Columns, And Dozens On The Layout.

How I Got The Numbers To Bet On The 0's Is By Using The First Listing Under The, "En Prison" Title Above, Is By Adding Up All The Chips Bet On The Layout ,(Before You Put Any Chips On The 0, Or 00), Which In This Case, Is 23 Chips. For This Technique You Just Multiply That Number, (23 Chips) By 12 It Comes To 276. Then, I Just Subtracted A Decimal Point From That, And Made It 27.6 Chips. We Use That Number On The 0, And 00. For The "Don't Apply Any Rules" sections, I Took The 23 Chip Total Before You Bet On The 0's, And The 9 Chips That Are Bet On Each Of The Columns/Dozens The 1st Example Above For Instance, Multiplied Them Together, (207), Divided That By 12, (17.25), Divided That By 3, (5.75), Double That Number, And It Comes To 11.5 Chips To Bet On Both Of Them. Bringing Grand Total Of Chips Bet To 45 Chips.

The Buy-In Was Pretty Simple Too. I Just Took The 9 Chip Total, (The Same Amount Of Chips Bet On Each Column, Or Dozen), And Multiplied That Number Times 3, Which Comes To Lucky Number 27. Then, Add 2 Decimal Points To It, And That's How I Got Our Buy-In Of 2,700 Chips.

I Was Wondering What Would Be The Best Way To Approach The Table With A System Like This, And I Think I Might Have An Answer. What I'm Purposing Is There Needs To Be 3 Individuals Working Together As A Team Consisting Of A Controller, And Two Spotters. What Would Happen Is That The Controller Would Give The Two Spotters Cash. Let Them Have Their Own Color Of Chips, And Bet For Himself/Herself On The First Dozen Bets, (The Inside, And Outside Bets), Plus The 0, And 00 Locations. The Other Two Would Be Working Independently Of Each Other On Their Section Of The Layout Using More Cash From Their Bankroll Whenever Needed, And When It's All Said And Done, Everybody Keeps The Money That They've Won. Wouldn't That Be Awesome?

Steve

  • Administrator
  • Hero Member
  • *****
  • Posts: 1865
Re: Divided By 12 Technique
« Reply #1 on: November 23, 2010, 08:27:28 AM »
Ultimately the reason this wont work is because you are considering the table, and not the wheel where it all actually happens. I'm sorry but you really are wasting your time.

Code Blue

  • Newbie
  • *
  • Posts: 24
Re: Divided By 12 Technique
« Reply #2 on: November 23, 2010, 09:27:16 AM »
Hi Steve.  I respect your judgment as well, but for the life of me I can't seem to find why nobody is getting the same results from it as I am.  I've been over this with tech support.  There's nothing wrong with the software, or my computer.  I'm really am at a loss here.  I can't figure it out here.  But, I won't post anymore of these things anymore, because I know it will only spark controversy, and discontent throughout the forum.  I just think I'm getting the row deal. I wish you would reconsider, and run them again.

I really don't think they're all that bad, or are for lack of potential, "worthless".  People are always asking, "It just looks like your trying the shotgun approach thinking that something might come up". Or they'll say, "I can't tell what your trying to do", and it just seems to me that people are passing judgment on me without even looking at it. I've explained everything about the system in my threads about how the inner working of the placements work, and yet people are still asking questions. They can't seem to figure out what I'm talking about.  If they would only plug in the numbers, and follow the instructions it would become clear as day that there is a perfectly logical method drawn out for you guys here. So, say what you will, because I know I got it comin'. Cold Blue

Steve

  • Administrator
  • Hero Member
  • *****
  • Posts: 1865
Re: Divided By 12 Technique
« Reply #3 on: November 23, 2010, 12:44:02 PM »
It doesnt matter what you cover on the table if you are not basing your predictions on physics and where the ball is more likely to land. Your bet selections are combinations like splits - they are no different to random bet selection.

Try it with flat bets - no progression. If a method does not win consistently without progression, the system is ineffective. Why? Because in such a case, all you're doing is changing the rate of bankroll decay, not actually changing the edge.

See www.genuinewinner.com/truth.html and if you understand the principles, you'll know your method simply cannot work in the long term. It really is no different to random betting with progression.

Code Blue

  • Newbie
  • *
  • Posts: 24
Re: Divided By 12 Technique
« Reply #4 on: November 23, 2010, 01:53:42 PM »
I just thought that if you bet more money each time you win, you can double your money with each new progression.  As for a stand alone bet, I have some examples I would like to show you.  They're also repetition events. The only problem is, if I'm not mistaken, it's never going to work in the long run any way, because all repetition flat bet strategies are doomed to failure. The gravity of the situation in general takes over.  As for the physics of the game, I only have a high school diploma.  I did take physics then, but that was 25 years ago.  It's got to be one heck of a equation to be able to predict the vicinity of a spin. Let me think about it for a while.  Maybe something will come to mind.  Thanks For The Advise.

Steve

  • Administrator
  • Hero Member
  • *****
  • Posts: 1865
Re: Divided By 12 Technique
« Reply #5 on: November 23, 2010, 03:14:12 PM »
It is not one heck of an equation - it is not rocket science. See www.genuinewinner.com/truth.html

I'm being direct with you and I'm trying to help - you are wasting your time.

Code Blue

  • Newbie
  • *
  • Posts: 24
Re: Divided By 12 Technique
« Reply #6 on: November 23, 2010, 07:52:27 PM »
Check it out Steve, the fact is, is that if you bet a chip on the dozens, and it pays off. The layout doesn't know what the wheel is doing, but It does matter. Because if it had of been bet somewhere else, (like in a different dozen), it would've been lost.   You can't just bet on all 3 dozens, and expect to win. So, I'm here to tell ya, chip placement matters! Chip placement matters with the columns too! You have to be betting in that section in order to get paid.

Plug in the numbers, and you can't miss the distinct pattern that is woven into the betting strategy using the same bets to pay off no matter where it lands on the wheel.  Any Other Organizational technique will be totally erratic with too much fluctuation to use. The trick is you have to leave the ball with no where to go except for into your arms.

Follow the pattern of 9 chips per quadrant with interlacing betting patterns that use the same bets in a front, back, or side to side directions. All of these bets come into play when the ball lands on any of the 12 quadrants effecting both the column bets, and the dozen bets. By giving you the continuity of having the same amount of chips bet on each column, or dozen that are in conjunction with the winning number's location on the layout, you can get predictable results when you place your bets knowing that you'll get the same answer whether you bet either up, and down, or right, to left.  

I still don't think anyone has figured out exactly what I'm trying to explain with these betting positions to where you have the same amount of chips as was bet on each one of the other quadrants on the layout. Where chip placements are important, and do matter. It's a three dimensional world out there, and where you place your bets does matter. Maybe this can shed some light on the subject, and explain what I'm talking about.  If you expect the profit margin to never stop, don't even bother. Oh, and I almost forgot, if you want to know how I got the numbers to bet on the 0's, or what the correlation between the 0's, and the rest of the layout is, please read the paragraphs written below the betting examples.  Thanks

Cordon' Blu'

12/24

"En Prison"

1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 2nd Dozen, 2nd Column Of 12, And Numbers 7,10,27,30
20.5 Chips On 0, And 00
64 Total
2,700 Buy-In
2nd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,10,27,30
3 Chips On 2nd Dozen, And 2nd Column Of 12
24.5 Chips On 0, And 00
76 Chips Total
3,300 Buy-In
3rd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,17,20,25,27,28,30
4 Chips On 2nd Dozen, And 2nd Column Of 12
31 Chips On 0, And 00
96Total
4,200 Buy-In
4th
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 17,20,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,9,10,12,25,27,28,30
5 Chips On 2nd Dozen, And 2nd Column Of 12
34.5 Chips On 0, And 00
100 Total
4,500 Buy-In

Roulette Xtreme "Don't Apply Any Rules"

1st
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 2nd Dozen, 2nd Column Of 12, And Numbers 7,10,27,30
15.5 Chips On 0, And 00
54 Total
2,700 Buy-In
2nd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 9,12,17,20,25,28,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,10,27,30
3 Chips On 2nd Dozen, And 2nd Column Of 12
19 Chips On 0, And 00
65 Total
3rd
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 2/5,16/19,18/21,32/35
2 Chips On 7,9,10,12,17,20,25,27,28,30
4 Chips On 2nd Dozen, And 2nd Column Of 12
24 Chips On 0, And 00
82 Chips Total
4,200 Buy-In
4th
.5 Chips On 7/10,9/12,25/28,27/30
1 Chip On 17,20,2/5,16/19,17/20,18/21,32/35
2 Chips On 7,9,10,12,25,27,28,30
5 Chips On 2nd Dozen, And 2nd Column Of 12
24.5 Chips On 0, And 00
84 Total
4,500 Buy-In

The Way The Inside Bets Work In These Examples Is By Using The Same Number Of Chips On Each Column, Or Dozen. In The First Betting Example Listed Above Under, "En Prison" That Number Is 9 Chips. Let's Take The 1st Dozen For Example: First We Need To Add Up All The Inside Bets That Are In Conjunction With This Dozen. Those Bets Are The 1 Chip Bets On 9,12,2/5. Plus, The 2 Chips Bet On 7, And 10. Then, We Need To Factor In The 2 Chips Bet On The Outside Of The Layout That Are In Relation To This Dozen. That Bet Is The 2 Chips On The 2nd Column Of 12. Which Brings Our The Total Chip Count For This Dozen To 9 Chips.

Now Let's Look At The Column Bets. Using The 2nd Column For Example: There Are 5 Inside Bets In Relation To This Column. They're The Chips Bet On 17,20,2/5,17/20,32/35. Then, I Included The 2 Outside Bets Which Are The 2 Chips Bet On The 2nd Dozen, And 2nd Column Of 12. That Gives Us Our 9 Chip Total For This Column. The Same Thing Will Happen With All Of Columns, And Dozens On The Layout.

How I Got The Numbers To Bet On The 0's Is By Using The First Listing Under "En Prison" Sections, I Added The 23 Chips, And The 9 Chips Together, (32) Doubled That, (64) And Used That For The Grand Total. So, If 64 Chips Is The Grand Total, And There Are Only 23 Chips On The Layout, Then The Remainder Of 64, And 23 Comes To 41 Chips. Split That In Half, And You Get The 20.5 Chip Total For Each Of The 0, And 00 Bets. As For The, "Don't Apply Any Rules" Section, Is Pretty Close To The On The, "En Prison" One's. You Just Add The 23, And 9 Together For 32 Chips. Multiply That Number By 36, (1152), Divided That By 24, (48), And Divided That Number By 3. Leaving 16 Chips To Bet On Each One Of The 0, And 00 Locations.

The Buy-In Was Pretty Simple Too. I Just Took The 9 Chip Total, (The Same Amount Of Chips Bet On Each Column, Or Dozen), And Multiplied That Number Times 3, Which Comes To Lucky Number 27. Then, Add 2 Decimal Points To It, And That's How I Got Our Buy-In Of 2,700 Chips.

I Was Wondering What Would Be The Best Way To Approach The Table With A System Like This, And I Think I Might Have An Answer. What I'm Purposing Is There Needs To Be 3 Individuals Working Together As A Team Consisting Of A Controller, And Two Spotters. What Would Happen Is That The Controller Would Give The Two Spotters Cash. Let Them Have Their Own Color Of Chips, And Bet For Himself/Herself On The First Dozen Bets, (The Inside, And Outside Bets), Plus The 0, And 00 Locations. The Other Two Would Be Working Independently Of Each Other On Their Section Of The Layout Using More Cash From Their Bankroll Whenever Needed, And When It's All Said And Done, Everybody Keeps The Money That They've Won. Wouldn't That Be Awesome? And The Best Thing Is, These Examples Listed Under, "Don't Apply Any Rules" Are All Within The Confines Of Table Limits.


ShelbyGT

  • Newbie
  • *
  • Posts: 36
Re: Divided By 12 Technique
« Reply #7 on: November 24, 2010, 08:46:01 AM »
steve is right you are wasting your time